x=317n=350Success rate(p) = x/n = 0.9057?= 0.1Z?/2 = 1.282 Null Hypothesis = Ho: p = 0.90  Alternative Hypothesis = H1 : p > 0.90z = p? – p /(square root (p (1-p))/n)= (317/350) – 0.90/ square root((0.90)(1-0.90))/350= 0.0057142857 / 0.0160356727=0.3563471553 = 0.3563Zo = 0.3563Critical ValueZ ?/2 = 1.282 |zo | < | z alpha | p-value: right tail – Ha : ( p > 0.35635 ) = 0.36079p?= x/n  317/350 =  0.9057142857 Ho : 0.3563H1: 0.36079There are 317 (2s) and 33 (1s)

QUESTION :

Based on your sample proportion, what is the probability of randomly choosing 3 of the 350 participants and finding all 3 that would not purchase another Lexus ?(calculations)