The question is The shortest side of a triangle measures 7m. The lengths of the other 2 sides are consecutive integers – the hypotenuse being the longer of the two, find the lengths of the other two:This is what I keep getting!(x+2)^2=x^2+7^2(x+2)(x+2)=x^2+49x^2+4x+4=x^2+49-x^2 -49 -x^2 -494x+53=0 -53 -53 4/4 -53/4 = -13.25
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