The question is The shortest side of a triangle measures 7m. The lengths of the other 2 sides are consecutive integers – the hypotenuse being the longer of the two, find the lengths of the other two:This is what I keep getting!(x+2)^2=x^2+7^2(x+2)(x+2)=x^2+49x^2+4x+4=x^2+49-x^2    -49 -x^2  -494x+53=0     -53  -53 4/4 -53/4 = -13.25